#Question 4
mean_1 = 50
n_1 = 36
std_1 = 42
#a_1 = 0.05 NOPE
a_1 = 1.96
lower_1 = mean_1 - (std_1/sqrt(n_1))*a_1
upper_1 = mean_1 + (std_1/sqrt(n_1))*a_1

cat(lower_1,"-",mean_1,"",upper_1)
#Question 5
## Higher confidence -> lower accuracy -> less accurate estimate -> greater range
## ~~Bigger n -> greater range -> greater standard deviation -> ?~~ NOPE
## Bigger n -> smaller standard error (std_1/sqrt(n_1)) -> smaller confidence range 

#Question 6

std_2 = 15
e_2 = 10 #?
# 10 = 15/sqrt(n) -> sqrt(n) = 15/10 -> n_2 = 1.5 #nope
#1.96*stderr_2 = e_2 (10)
#stderr_2 = 5.102041
#n_2: 5.102041 = 15/sqrt(n)
#15/5.102041 = sqrt(n)
# 10 = 1.96*(15/sqrt(n))