vault backup: 2025-01-15 18:28:22
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@@ -145,8 +145,8 @@ $$
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g(p) = p \\
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g(\neg A) = \Box\neg g(A) \\
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g(A \to B) = \Box g(A) \to \Box g(B)\\
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g(a \land B) = \Box g(A) \land \Box g(B)
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g(A \lor B)= \Box g(A)\lor \Box g(B)
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g(a \land B) = \Box g(A) \land \Box g(B) \\
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g(A \lor B)= \Box g(A)\lor \Box g(B)\\
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\end{align}
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$$
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